please answer 1st question
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height = 200m
let mass of the aluminium piece = m kg
Potential energy of the mass = mgh = m×10×200 = 2000m Joule
when it falls on the non-conducting slab, there is no energy loss by heat. So the potential energy is converted to internal heat energy of the slab.
Let the increase in its temperature is T.
specific heat of aluminium, s= 210 cal/kg.℃ = 879 J/kg℃
thus mgh = msT
=> 2000m = m×879×T
=> T = 2000/879
=> T = 2.28℃
Answer is A.
let mass of the aluminium piece = m kg
Potential energy of the mass = mgh = m×10×200 = 2000m Joule
when it falls on the non-conducting slab, there is no energy loss by heat. So the potential energy is converted to internal heat energy of the slab.
Let the increase in its temperature is T.
specific heat of aluminium, s= 210 cal/kg.℃ = 879 J/kg℃
thus mgh = msT
=> 2000m = m×879×T
=> T = 2000/879
=> T = 2.28℃
Answer is A.
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