Question

please answer 2 (i) question

Answer 1

Given : (√48 + √32)/(√27 - √18)

$=> \frac{4\sqrt{3} + 4\sqrt{2}} {3\sqrt{3}-3\sqrt{2}}$

On rationalizing the denominator, we get

$=> \frac{4 \sqrt{3} + 4 \sqrt{2}}{3 \sqrt{3} -3\sqrt{2}}*\frac{3\sqrt{3}+3\sqrt{2}}{3 \sqrt{3}+3\sqrt{2}}$

$=>\frac{36 + 24 \sqrt{6} + 24}{(3\sqrt{3})^2 - (3\sqrt{2})^2}$

$=> \frac{60 + 24 \sqrt{6}}{27 - 18}$

$=> \frac{12(5 + 2\sqrt{6})}{9}$

$=> \frac{4(5 + 2 \sqrt{6})}{3}$

Hope it helps!

Answer 2

√48+√32/√27-√18

4√3+4√2/3√3-3√2

4(√3+√2)/3(√3-√2)

we rationise it by 3√3-3√2

and we get

4(5+2√6)/3