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In ∆ABC and ∆AFE,
BC=FE (given)
AB=AF (all sides of square are equal)
⊾B=⊾F= 90⁰ (all angles of square are 90⁰)
Therefore, ∆ABC≃∆AFE (SAS criteria)
AC=AE (CPCT)——>i
In ∆ACG and ∆AEG,
⊾AGC=⊾AGE=90⁰ (given)
AG=AG (common side)
AC=AE (proved in i)
Therefore, ∆ACG≃∆AEG (SAS criteria)
Please mark me as brainliest.
BC=FE (given)
AB=AF (all sides of square are equal)
⊾B=⊾F= 90⁰ (all angles of square are 90⁰)
Therefore, ∆ABC≃∆AFE (SAS criteria)
AC=AE (CPCT)——>i
In ∆ACG and ∆AEG,
⊾AGC=⊾AGE=90⁰ (given)
AG=AG (common side)
AC=AE (proved in i)
Therefore, ∆ACG≃∆AEG (SAS criteria)
Please mark me as brainliest.
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