Question

please answer............
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Answer 1

$\huge\star\underline\mathfrak\pink{Answer:-}$

Given quadratic equation = √3x² - 8x + 4√3 = 0

We should factorize the equation first.

=√3x²-6x-2x+4√3 = 0

= √3x(x-2√3)-2(x-2√3) = 0

= (√3x-2) (x-2√3) = 0

= (√3x-2) = 0 , (x-2√3) = 0

= x = 2/√3 , x = 2√3.

Answer 2

$\huge\underbrace\mathfrak \red{ANSWER }$

Given quadratic equation = √3x² - 8x + 4√3 = 0

We should factorize the equation first.

=√3x²-6x-2x+4√3 = 0

= √3x(x-2√3)-2(x-2√3) = 0

= (√3x-2) (x-2√3) = 0

= (√3x-2) = 0 , (x-2√3) = 0

= x = 2/√3 , x = 2√3.

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