Question

Please answer 2nd question ☝

Answer 1

Answer:

Let father age is a

Sons age is b

a-2/b =5

a-2=5b

a-5b=2

a+2=8+3b

a-3b=6

2b=4

B=2

A=12

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• 2 years ago father's age was 5 times the son's age
• 2 years hence father's age will be 8 more than 3 times the son's age

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• find their present ages = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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let the father's age be x

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let the son's age be y

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2 years ago :-

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father's age = x - 5

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son's age = y - 5

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5 ( y - 2 ) = x - 2

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5y - 10 = x - 2

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5y - x = 10 - 2

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5y - x = 8 ----- ( i )

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2 years hence :-

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8+ 3 ( y + 2 ) = x + 2

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8+ 3y + 6 = x + 2

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3y + 14 = x + 2

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x - 3y = 14 - 2

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x - 3y = 12 ----- ( ii )

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• Adding eq ( i ) and ( ii )

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5y - x + x - 3y = 12 + 8

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5y - 3y = 12+ 8

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2y = 12+ 8

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2y = 20

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y = 20 / 2

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y = 10

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• putting value of y in eq ( ii )

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x - 3y = 12

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x - 3 × 10 = 12

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x - 30 = 12

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x = 12 + 30

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x = 42

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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• father's age = 42 years
• son's age = 10 years