Question

please answer...............................................

Answer 1

Answer:

hello

Step-by-step explanation:

Iam something

Answer 2

Answer:

Identity used

$log_{x}(y) = z \: \\ then \: y \: = {x}^{z}$

$log_{x + 2}( {17x}^{2} - 6x + 8) = 3$

${17x}^{2} - 6x + 8 = {(x + 2)}^{3} \\ {17x}^{2} - 6x + 8 = {x}^{3} + 3 \times {2}^{2} \times x + 3 \times {x}^{2} \times 2 + {2}^{3} \\ {17x}^{2} - 6x + 8 = {x}^{3} + 12x + 6 {x}^{2} + 8 \\ {x}^{3} - {11x}^{2} + 18x = 0 \\ x( {x}^{2} - 11x + 18) = 0 \\ x( {x}^{2} - 2x - 9x + 18) = 0 \\ x(x - 2)(x - 9) = 0 \\ x = 0 \: or \: 2 \: or \: 9$