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Answer:
S₆ = 120
Step-by-step explanation:
Given: a₁ = a = -5 and a₆ = 45
w.k.t., aₙ = a+(n-1)d, where a is first term and d is common difference of A.P.
⇒ a₆ = a+(6-1)d
or 45 = -5 + 5d
or 5d = 45+5 = 50
or d = 10
w.k.t., Sₙ = n*[2a + (n-1)d]/2
⇒ S₆ = 6 * [2(-5) + (6-1)d] /2
or S₆ = 3 * [-10 + 5*10]
or S₆ = 3 * [-10 + 50]
or S₆ = 3 * 40
or S₆ = 120
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