Chemistry, asked by eshwarkarthikeya, 1 year ago

Please answer 34 fastly please

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Answered by shanayakh0792
2

a)

mark as brainliest

Answered by sdevikrishna00855
1

The four options in the 34 th question is wrong. None of the statements are correct.

A) There is only one dative bond/co-

ordinate bond in

(NH4) +

B) bond strength is in the order s-s>s-

p>p-p

C and D)

After hybridization the shapes

which are formed are all due to

sigma bond not pi bond . Because

pi bond doesn't take part in

hybridization . Hybridization is

called mixing of bond and only

sigma bonds are evolved in it .

When ever pi bond is present it will

make double or triple bond.

Moreover, pi bond are weaker than

sigma bond and pi bbonds

between atom is always formed

secondarily to the sigma bond. As

such pi bond don't alter the basic

idealized geometry of molecule

Hope you understand

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