Please answer 36th question (◍•ᴗ•◍)❤
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Let height be h
now,
we can say
tanx°=h/AC
as tanx=3/4 so,
3/4=h/AC
4h/3=AC...................I)
tany=h/(AC+150)
Tany=5/7 (given)
5/7 =h/(AC+150)
5AC+750=7h
AC=(7h-750)/5
Comparing eq I) and ii)
(7h-750)/5 =4h/3
21h-2250=20h
h=2250
Hence height will be 2250m
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helo kannad a na hantha kelde??
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