Question

Please answer................

Answer 1

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THE ANSWER IS HERE,


$= > \: 4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3} = 0$

$= > \: 4 \sqrt{3} {x}^{2} + 8x - 3x - 2 \sqrt{3} = 0$

$= > \: 4x( \sqrt{3} x + 2) - \sqrt{3} ( \sqrt{3} x + 2) = 0$

$= > \: (4x - \sqrt{3} )( \sqrt{3} x + 2) = 0$

$= > \: x = \frac{ \sqrt{3} }{4} \: \: and \: \: \frac{ - 2}{ \sqrt{3} }$

Sum of the zeroes,


$= > \: \frac{ \sqrt{3} }{4} - \frac{2}{ \sqrt{3} }$

$= > \: \frac{3 - 8}{4 \sqrt{3} }$

$= > \: \frac{ - 5}{4 \sqrt{3} }$


:-)Hope it helps u.