Physics, asked by Anonymous, 1 year ago

please......... answer

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maddyanu: hey pls post a clen photo
maddyanu: sorry clean
BRAINLYY: find the area under graph
Anonymous: ok wait I'll send

Answers

Answered by guuda
0
is it 50m...............

displacement is the shortest distance which is calculated by taking the velocity with which the body has completed the shortest path......

displacement = velocity×time

displacement = 5×10= 50m

velocity of 5m/s is considered because the shortest distance between final and initial point is AE.
Velocity graph for AE represents a velocity of 5 m/s in total time 10s.....

so displacement = 5×10 =50m
...

guuda: now hv u got explaination or not ?
Anonymous: yes
Anonymous: please answer my questions i have asked now
guuda: sry sry sry.....the displacement =velocity × time.....so answer must be 50m....
guuda: sry....now this answer is absolutely correct
Anonymous: its ok
guuda: sry....now this answer is absolutely correct
guuda: ok let me check ur question now
guuda: hv u asked it now???
Anonymous: please answer
Answered by BRAINLYY
0
It is Velocity and Time graph so we can say that A body is suffering this much Displacement from initial to final position in time taken.

Answer is the Area under graph since Area under graph would be equal to Quantity on Y-axis × Quantity on X-Axis

Hence, the Area under graph would give you

*Velocity* × Time

We know that Velocity × Time = Displacement

So Area Under Graph is the Answer
Find Area of ∆ ABF = 5
Area of BCFG = 4×5 = 20
Area of CGIE = 4×5 = 20
Area of ∆ CDE = 1/2 × 4 × 5 = 10

=> Total Area = 5+20+20+10

=> Total Displacement = 55 m
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