Question

please answer 5th one by miscellaneous application​

Answer 1

If 4tan theta = 3

then,

tan theta = 3/4

P/B. = 3/4

so,

P = 3 , B = 4

H = √ P² + B²

= √3² + 4²

= √ 9 + 16

= √ 25 = 5

so,

2 sec theta - 1 = 2k

2*5/4 - 1 = 2k

5/2 - 1 = 2k

5 - 2/2. = 2k

3/2. = 2k

3/4. = k

so, the value of k is 3/4