please answer 5th question please fast
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The outer diameter = d1 = 14 cm
so the outer radius = r1 = 14 / 2 = 7 cm
The inner diameter = d2 = 6 cm
so the inner radius = r2 = 6/2 = 3 cm
Height of pipe = 50 cm
Total Surface Area of Pipe
= 2πr1(h + r1) - 2πr2(h + r2)
= 2π [ r1(h + r1) - r2(h +r2) ]
= 2π [ 7(50 + 7) - 3(50 + 3) ]
= 2π ( 399 - 159)
= 2π (240)
= 2 × 22/7 × 240
= 10560 / 7
= 1508.57 cm2
= 1508.6 cm² ( approx.)
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so the outer radius = r1 = 14 / 2 = 7 cm
The inner diameter = d2 = 6 cm
so the inner radius = r2 = 6/2 = 3 cm
Height of pipe = 50 cm
Total Surface Area of Pipe
= 2πr1(h + r1) - 2πr2(h + r2)
= 2π [ r1(h + r1) - r2(h +r2) ]
= 2π [ 7(50 + 7) - 3(50 + 3) ]
= 2π ( 399 - 159)
= 2π (240)
= 2 × 22/7 × 240
= 10560 / 7
= 1508.57 cm2
= 1508.6 cm² ( approx.)
Hope you like it please mark as brainliest and follow me if you like my answer.
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