Question

please answer..............?

Answer 1

AB//CD
thrfr <BDC= <DBC
<DBC = 40°
In∆ABD
=<A +<B +<D = 180°
75° + 40° + <D = 180°
115°+ <D = 180°
<D = 180° - 115°
<D = 65°
<ADB =<DBC
Y= 65°
In∆DBC
<D+<C+<B = 180°
40°+ 65°+ <B= 180°
105°+<B= 180°
<B=180-105°
<B=75°