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let ABC be the triangle with BC as base
now draw a perpendicular from A on BC say at point M it will clearly bisect BC bcoz the two triangles formed are congruent
now apply Pythagoras their to triangle AMB we get
5² =3 ²+ h² where is height
on solving h = 4
now draw a perpendicular from A on BC say at point M it will clearly bisect BC bcoz the two triangles formed are congruent
now apply Pythagoras their to triangle AMB we get
5² =3 ²+ h² where is height
on solving h = 4
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