Please answer 74 and 75 question
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74) Horizontal velocity at max height = ucos 30°
=10×√3/2
=5√3
75) u=23m/s
t=5/23
v=u+gt
v=23+5/23*10
v=23+50/23
v={(23*23)+50}÷23
v={529+50}/23
v=25.17m/s
=10×√3/2
=5√3
75) u=23m/s
t=5/23
v=u+gt
v=23+5/23*10
v=23+50/23
v={(23*23)+50}÷23
v={529+50}/23
v=25.17m/s
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