Physics, asked by Anonymous, 1 year ago

Please answer 74 and 75 question
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Answered by Anonymous
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74) Horizontal velocity at max height = ucos 30°
                                                          =10×√3/2
                                                           =5√3

75) u=23m/s
       t=5/23
      v=u+gt
      v=23+5/23*10
      v=23+50/23
      v={(23*23)+50}÷23
      v={529+50}/23
      v=25.17m/s
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