Question

please answer........

Answer 1

In inclined plane !
F=mgsin o +umgcoso
Also, F=ma
we get,
ma=mgsino+umgcoso
a =gsino+ ugcoso
a =g(sino +ucoso)
a =g(sin370+0.5 × cos370)
a =10(0.6 +0.5×0.8)
a =10(0.6+0.4)
a =10×1=10m/s square
we know
v square _u square =2as
final velocity (v)=0(as it finally comes on rest)

Initial velocity (u)=20m /s
acceleration =10m /s square
v square _u square =2as
s=v square _u square / 2a
s=0_20 square/2×10


s= _20 m

Answer 2

hi mate

here's your answer

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