Please answer 8 th and 9th question
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8) 1^3 - 6× 1^2 + 11×1 -6
= 1-6+11-6
=12-12 = 0
(3^3)-(6×3^2)+(11×3)-6
=27-54+33-6
60-60 = 0
Yes both 1 and 3 are zeroes
9) AC=BD
AB+BC=BC+CD
Cancel BC on both sides
AB = CD
HENCE PROVED
Hope this helps
= 1-6+11-6
=12-12 = 0
(3^3)-(6×3^2)+(11×3)-6
=27-54+33-6
60-60 = 0
Yes both 1 and 3 are zeroes
9) AC=BD
AB+BC=BC+CD
Cancel BC on both sides
AB = CD
HENCE PROVED
Hope this helps
smiriti007:
welcone
welcome
Answered by
0
Answer:
8) f (x)=x^3-6x^2+11-6
If x=1
F(1)=1-6+11-6
=12-12
=0
Therefore yes
If x=3
f(3)=27-54+33-6
=60-60
=0
Therefore yes
9) AC=BE
AB+BC=BC+CD
AB=CD
Hence proved
Hope you will satisfied with this
9: - If AC=BD THEN
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