Question

please answer 9th question it is so much important for me please

Answer 1

hey mate here is ur answer!!☺☺

hope my answer help u

Answer 2

$Given : \frac{7 + 3\sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3\sqrt{5}}{3 - \sqrt{5}}$

$= > \frac{(7 + 3\sqrt{5})(3 - \sqrt{5}) - (7 - 3\sqrt{5})(3 + \sqrt{5})}{(3^2) - (\sqrt{5})^2}$

$= > \frac{21 - 7\sqrt{5} + 9\sqrt{5} - 15 - 21 - 7\sqrt{5} + 9\sqrt{5} + 15}{9 - 5}$

$= > \frac{4\sqrt{5}}{4}$

$= > \sqrt{5}$

So,

$= > a + b\sqrt{5} = 0 + 1 * \sqrt{5}$

Therefore, a = 0, b = 1.

Hope it helps!