Question

please answer , aa fast as possible​

Answer 1

Answer:

when p =1, then

13+19(1)/4

32/4

=8

Answer 2

Step-by-step explanation:

Given :-

Let P(x) = a0 + a1x + ...+ an x^n be a polynomial with integer coefficients and ai € (0,1) for all i = 0,1,2,...,n.

Given P(√2) = 13+19√2

To find :-

Find the value of P(1)/4 ?

Solution :-

Given that :

P(x) = a0 + a1x + ...+ an x^n is a polynomial with integer coefficients and ai € (0,1) for all i= 0,1,2,...,n.

Given that P(√2) = 13+19√2

So it is clear that P(x) = 13+19x

It is a linear Polynomial

Now Put x = 1 then

P(1) = 13+19(1)

=> P(1) = 13+19

=> P(1) = 32

The value of P(1) = 32

Now,

The value of P(1)/4

=> P(1)/4 = 32/4

=> P(1)/4 = 8

Answer:-

The value of P(1)/4 for the given problem is 8

Points to know:-

• P(x) = a0 + a1x + ...+ an x^n is an nth degree Polynomial.

• P(x) = ax+b is a linear Polynomial.