Question

please answer above questions any 3 u can give answer please help me please​

Answer 1

Answer:

it is a trigonometry chapter

Answer 2

Hi I can help u there

ii) Take lcm which will be 1 - sin^2 using a^2 - b^2 identity

so it will be 1 - sin thita + 1 + sin thita / cos ^2 thita. using trigonometric identities

2/ cos^2thita then it will be = 2 sec^2thita.

iii) (1+tan^2) (1-sin^2) = 1. (a+b)(a-b)= a square- b square

sec^2 × cos^2 = 1. using trigonometric identities

1/cos^2 × cos^2 = 1. cos = 1 / sec

1= 1

therefore LHS = RHS

iv) I m directly solving this Q. as it is similar

using identities we get. cosec^2 × sin^2

1/ sin^2 × sin^2

1 = 1 LHS= RHS

Hope you understood!