Question

please answer according to the points
WITH EXPLANATION ELSE I'LL REPORT IT!!!!!!!​

Answer 1

Answer:

∆l=0.5mm

N=100×isions

zero correction = 2 division reading = measured value + zero correction

=8×0.5mm+(83-2)×0.5/100

=4mm+81×0.5/100

=4.405 is the correct

Yrr mera answer bilkul shi h phir report kyu kr rhe ho ....

Answer 2

Answer:

Length of pitch of screw gauge = 0.5mm

= 0.5 = 0.005mm

100

Zero error = 2×0.005

Zero error = 0.01mm

Final reading = 8 (MSD) + 83LC

Final reading = 8 (0.5)+83 (0.005)

Final reading = 4+ 0.415.

Final reading = 4.415mm.

Therefore the diameter of the wire is 4.415mm.

Hope it helps u Maths Aryabatta sir .

If u think this answer is good mark it as BRAINLIEAST .