Physics, asked by Vincent1853, 1 month ago

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Answers

Answered by Mbappe007
2

Answer:

\large{ \underline{ \underline{ \red{\tt{Answer \: (1)}}}}}

Answer(1)

Given :

Length of the rectangle = 12 cm

Breadth of the rectangle = 10 cm

To Find :

Area and perimeter of the rectangle.

Formulae used :

For calculating the area of rectangle, formula is given by,

\boxed{ \bf{Area_{(Rectangle)} =l \times b}}

Area

(Rectangle)

=l×b

For calculating the perimeter of rectangle, formula is given by,

\boxed{ \bf{Perimeter_{(Rectangle)} = 2(l + b)}}

Perimeter

(Rectangle)

=2(l+b)

Here,

{l}l = length

b = breadth

Calculations :

\dag \: { \pink{ \sf{ \underline{ \underline{Calculating \: the \: area \: of \: rectangle :}}}}}†

Calculatingtheareaofrectangle:

Using formula,

\star{\boxed{ \bf{Area_{(Rectangle)} =l \times b}}}⋆

Area

(Rectangle)

=l×b

Putting the values,

\longrightarrow⟶ Area of rectangle = length × breadth

\longrightarrow⟶ Area of rectangle = 12 × 10 cm

\longrightarrow⟶ Area of rectangle = 120 cm²

Hence, area of rectangle is 120 cm².

\dag \: { \pink{ \sf{ \underline{ \underline{Calculating \: the \: perimeter \: of \: rectangle :}}}}}†

Calculatingtheperimeterofrectangle:

Using formula,

\star{\boxed{ \bf{Perimeter_{(Rectangle)} = 2(l + b)}}}⋆

Perimeter

(Rectangle)

=2(l+b)

Putting the values,

\longrightarrow⟶ Perimeter of rectangle = 2 (l + b)

\longrightarrow⟶ Perimeter of rectangle = 2 (12 + 10)

\longrightarrow⟶ Perimeter of rectangle = 2 × 22

\longrightarrow⟶ Perimeter of rectangle = 44 cm

Hence, the perimeter of rectangle is 44 cm.

____________________________________

\large{ \underline{ \underline{ \red{\tt{Answer \: (2)}}}}}

Answer(2)

Given :

Number of boys in class = 20 Boys

Number of girls in class = 15 girls

To Find :

Ratio of girls to boys

Boys to whole class

Calculations :

\underline{ \underline{ \bf{ \purple{1) \: Ratio \: of \: girls \: and \: boys \: - }}}}

1)Ratioofgirlsandboys−

Given that,

• Number of girls = 15 girls

• Number of boys = 20 boys

Now, according to the question, let's find the ratio of girls to Boys.

→ Number of boys : Number of girls

Now, evaluating,

\longrightarrow⟶ 20 : 15

\longrightarrow⟶ 20/15

Cancelling the numbers and converting in simplest form,

\longrightarrow⟶ 4/3

In ratio,

\longrightarrow⟶ 4 : 3

Therefore, ratio of girls to Boys is 4 : 3.

\underline{ \underline{ \bf{ \purple{2) \: Ratio \: of \: boys \: to \: whole \: class - }}}}

2)Ratioofboystowholeclass−

• Total number of students = 35 students

→ 15 + 20

→ 35 students

And, number of boys is 20 Boys.

\longrightarrow⟶ 20 : 35

\longrightarrow⟶ 20/35

Cancelling the numbers and converting in simplest form,

\longrightarrow⟶ 4/7

In ratio,

\longrightarrow⟶ 4 : 7

Therefore, ratio of boys to whole class is 4 : 7.

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