Question

please answer all of these​

Answer 1

2)we know average velocity is equal to total distance by total time.

Let's say total distance to be covered as s

thus total distances s.

now we kno time is equal to displacement•velocity

there for time taken to complete first part of the journey is (s/2v1) and second is (s/2v2)

on additing we get total time is (s(v1+v2)/2v1v2)

dividing the first one by second we get

(2v1v2/v1+v2)

3) from distance•velocity equals time

we have t1=S1/v1 and t2=S2/v2.

thus we get average velocity as (S1+s2)/(t1+t2) on solving we get the answer.

4) we know distance is equal to speed into time.

saying distance covered in first period of time is 50t and second interval of time is 60t we have

average velocity as (110t/2t) giving us 55km/hr.

5)we know velocity is derivative of position to time.

saying f(t)=6t²-5t+2

f'(t)=12t-5

intial velocity signifies velocity at t=0

puttin t=0 we get v=-5m/s

Answer 2

Answer:

hope the attachment helps