Please answer all the given questions.
Attachments:
Answers
Answered by
1
Answer:
(a) P = V²/R
When both the bulbs are given same voltage
R ∝ 1/P
Hence, resistance will be more for the given which is dissipating less power.
Resistance is more for 25 Watt bulb and by 4 times(100/25 W).
(b) (I have posted the graph below)
(c) One ampere can be defined as the unit of electric current and that is equal to the flow of one coulomb of charges per second.
(d) ANS. = 3600C
Explanation:
The electric charge is given by:
Q = I × t
Corresponding SI units:
coulomb (C) = ampere (A) ∙ second (s)
Where 'I' is the electric current and 't' is the time (duration).
by the formula Q = I t putting values....
Q= 0.2 × (5 ×60×60)sec.= 3600C
Hope it helps you..
Please mark me as Brainliest..
Attachments:
Similar questions