Question

please answer all the questions​

Answer 1

Q.1

Polynomial is x^2 +(a+1)x +b

Zeros are 2 and -3

If we replace zeros by x the polynomial will be equal to 0

If x=2

(2)^2 + (a+1)2 + b =0

4 + 2a + 2 + b = 0

2a + b + 6 =0 ..... 1st eq

If x=-3

(-3)^2 + (a+1)(-3) + b =0

9 - 3a -3 + b =0

b-3a +6 =0 ..... 2nd eq

Solving 1st and 2nd eq we get -

a=0 b= -6

So option D is correct

PLEASE MARK AS BRAINLIST