Chemistry, asked by ritika37, 1 year ago

please answer all these questions...fasttt fasttt fasttt guys

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Answered by Prakasham
4
56.the answer is c
. this is because option 3 is a tertiary carbonation and we know that tertiary carbonation is more stable as it tends to gain electrons
57.the answer is c
as we know that the carbon free radical and carbonation tends to acquire sp3 hybridization and carbanoin has sp2 hybridization
58.the answer is b
in 1, it is a primary carbanoin and it doesn't require any more electrons and by the options given, it is more stable.
in the second one it is being held by an electron withdrawing group but is is in direct connection with the carbanoin si it gives back donation to it and it is the second more stable carbanoin.
in third one it is a secondary carbanoin and as well as it undergoes tautomerism as it is the most activated group in it but it is electron rich so it is the least stable
finally in the fourth one it is a primary carbanoin but the connected carbon has two electron donating groups so its donating capacity is more than that of 1st and 2nd one but the property of carbanoin is to donate electrons so it is the third stable one.
55. I think so the answer is d
as in a it contains oxygen group and if we hydrogenated it, the double bond will be shifted to the cycle structure bye there are double bonds in it so it will become a cumulated double bond which is least stable and there is no chance to hydrogenate In b and in c so d is the accurate answer

ritika37: thanks a lot friend
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