Question

please answer!!!!!___________--/--- ---/-- ______
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Answer 1

Answer:

Cos(270 - theta) +sin(180-theta)

-sin theta + sin theta

= zero

Reason :

cos( 270−Θ)=cos[180+(90−Θ)]

But we know that cos(180 + Θ)=−cosΘ)

∴ cos [ 180 + ( 90 - Θ)]=−cos(90−Θ)

But cos (90 -Θ)=sinΘ)

∴ cos(270−Θ)=−sinΘ_

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(180-theta)

Answer 2

$Cos(270\degree - \theta) + sin( 180\degree - \theta) = \underline {\red {0}}$

Explanation:

We know that,

• Cos(270°- A) = -sinA
• sin(180° - A) = sinA

$\red{ Cos(270\degree - \theta) + sin( 180\degree - \theta)}\\= -sin\theta + sin \theta \\= 0$

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