Question

Please answer and also give a step-by-step explanation

Answer 1

Solution:-

Given,

∠ADB = 45°

WKT

☞ Radii of a circle and tangents drawn to the point of contact are perpendicular to each other.

∠OAD = ∠OBD → 90°

So, In Quadrilateral AOBD

$→\;{\sf{∠OAD+∠OBD+∠ADB+∠AOB = 360°}}$

$→\;{\sf{90°+90°+45°+∠AOB = 360°}}$

$→\;{\sf{225°+∠AOB = 360°}}$

$→\;{\sf{∠AOB = 360°-225°}}$

$➝\;{\bf{∠AOB = 135°}}$

The Value of ∠AOB ◕➜ $\Large{\red{\mathfrak{135°}}}$

Hope It Helps You ✌️