Question

please answer and explain the qs in the attachment.​

Answer 1

We know that diagonal of rhombus are perpendicular to each other.

So angle AOB is 90 degree

So triangle AOB is right-angled triangle.

Let angle CAb =a

cos a=0.6

Given OB=8cm

tan a=

OA

OB

- eq. 1

sin a =

AB

OB

- eq. 2

tan a=

cosa

sina

-eq. 3

sina=

1−cos

2

a

- eq. 4

By equation 4 we get

sina=0.8

By equation 3 we get

tan a=

3

4

using equation 1 we get length of OA=6

By equation 2 we get length of AB =10

So Lenght of sides are 10 cm , length of major di