Question

Please answer and explain the questions 2 ....!
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Answer 1

Answer:

For the first one, it is tertiary amine

For the second one, it is aniline

The reason being Sn/HCl is a reducing agent which reduces nitro groups (-NO₂) to amino groups (-NH₂)

Hope this answer helped you :)

Answer 2

1. N,N - dimethylethanamine is the example for

[ c ] Tertiary amine

It is commonly known as Dimethylethylamine.

it's a tertiary amine as all the hydrogen atoms of ammonia are replaced by alkyl group leading to the formation of tertiary amine.

The amines are said to be simple when all the alkyl/aryl groups are same, and mixed when they are different.

In this question , there are two different types of alkyl groups replacing the hydrogen atoms of ammonia , one is ethyl and the other two are methyl.

2. Nitrobenzene reaction with Sn/Cl followed basic work , the resultant compound formed will be......

When nitrobenzene reacts with Sn/Cl , the resultant compound formed is [ b ] Aniline ( IUPAC name :- Aniline/Benzenamine ) .

Reduction of nitro compounds into amines is carried out by passing hydrogen gas in the presence of finely divided Nickel, palladium or platinum.

Also by reduction of metals in acidic medium.

In the same way, Nitroalkanes can be reduced to corresponding Alkanamines