Question

please answer and in return I'll vote you all 5.0 ​

Answer 1

o is the answer as according to thsi it is the answer

Answer 2

Solution :-

$\frac{1}{1 - \sin( \theta ) } + \frac{1}{1 + \sin( \theta) } = 2 \sec {}^{2} ( \theta)$

Take LHS

$\frac{1}{1 - \sin( \theta) } + \frac{1}{1 + \sin( \theta) }$

Now take LCM

$\frac{1 + \sin( \theta ) + 1 - \sin( \theta) }{[(1 - \sin\theta)(1 + \sin\theta)] } \\ \\ =\frac{2}{1 - \sin {}^{2} ( \theta) }$

We know that -

$1 - \sin {}^{2} ( \theta) = \cos {}^{2} (\theta)$

Hence,

$\frac{2}{ \cos {}^{2} ( \theta) } = 2 \sec {}^{2} ( \theta) \: \: \: \\ \\ \ \: \: \: \: hence \: \: \: proved$