Math, asked by Anonymous, 6 months ago

please answer anyone one of the above question
please
help me out...​

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Answered by Anonymous
3

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i)x^5\cdot x^3 = x^{5+3}= x^8

ii)\frac{x^8}{x^3}  = x^{(8-3)} = x^5

iii)(x^3)^2 = x^{3\cdot2}= x^6

iv)(5x^{-3}yz^2)^{-2 }= \frac{1}{\left(5x^{-3}yz^2\right)^2} = \frac{1}{\frac{25y^2z^4}{x^6}} = \frac{x^6}{25y^2z^4}

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Answered by Anomaverma
1

1. x^(5+3) = x^8

2. x^(8-3) = x^5

3 (x³)² = x^6

4. (3x²)³ = 27x^6

5. (5×1/x³×yz²)^-2 = x³/5×1/y×1/z²

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