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4. The total length of both ropes = (2x+3) + (3x-7)
= 5x - 4
5. Let the number be n
2x² + xy + 2y² + n = 3x² + 5xy
n = 3x² + 5xy - (2x² + xy + 2y²)
n = 3x² + 5xy - 2x² - xy - 2y²
n = x² + 4xy -2y²
6. Let the number be n
3a² - 4b² + 5ab - n = -a² - b² + 6ab
n = -a² - b² + 6ab - (3a² - 4b² + 5ab )
n = -a² - b² + 6ab - 3a² + 4b² - 5ab
n = -4a² + 3b² + ab
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Hope it helps :)
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Sorry sis I don't have power to inbox you but when I got the power I will sure inbox you...
happy eid ❤❤❤
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