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hiiiii friend his your answer -::angle CAB =50° and angle ABC =80°
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sum of angles =180°
angleADC+ angle ACD + angle CAD = 180°
90° ( right angle) + Angle ACD+ 50°= 180°
=90+ACD+50=180
ACD+140=180
ACD= 180-140
= 40°
angleACD = angle CAB = 40°
angle ABC= 90° ( right angle)
angleADC+ angle ACD + angle CAD = 180°
90° ( right angle) + Angle ACD+ 50°= 180°
=90+ACD+50=180
ACD+140=180
ACD= 180-140
= 40°
angleACD = angle CAB = 40°
angle ABC= 90° ( right angle)
SBhargavaAkash:
rong
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