please answer as fast as possible the product of 2 consecutive number is 506 what are the numbers
Answers
Answered by
1
Let the 2 consecutive numbers be x and x + 1.
Given that two consecutive numbers product if 506.
x( x + 1) = 506
x^2 + x = 506
x^2 + x - 506 = 0
x^2 + 23x - 22x - 506 = 0
x(x + 23) - 22(x + 23) = 0
(x + 23)(x - 22) = 0
x = -23, 22.
Therefore the two numbers are 22 and 23 (or) -22 and -23.
Hope this helps!
Given that two consecutive numbers product if 506.
x( x + 1) = 506
x^2 + x = 506
x^2 + x - 506 = 0
x^2 + 23x - 22x - 506 = 0
x(x + 23) - 22(x + 23) = 0
(x + 23)(x - 22) = 0
x = -23, 22.
Therefore the two numbers are 22 and 23 (or) -22 and -23.
Hope this helps!
siddhartharao77:
:-)
Answered by
1
Let the no. Be X and X+1
Then according to question
X (X+1) = 506
X^2 + X = 506
X^2 +X -506 = 0
X^2 + 23X - 22X -506 = 0
X(x+23) -22(X+23)= 0
(X+23) ( X-22) = 0
X = -23 or 22
However x cannot be negative.
Therefore X = 22
So the no.s are
X= 22
& X+1 = 23
If you satisfied mark it brainliest.
Your support is encouragement for us.
Then according to question
X (X+1) = 506
X^2 + X = 506
X^2 +X -506 = 0
X^2 + 23X - 22X -506 = 0
X(x+23) -22(X+23)= 0
(X+23) ( X-22) = 0
X = -23 or 22
However x cannot be negative.
Therefore X = 22
So the no.s are
X= 22
& X+1 = 23
If you satisfied mark it brainliest.
Your support is encouragement for us.
Similar questions