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Answers
Explanation:
Vab is scalar and unlike the convention followed for vectors, where R12= R2 -R1, we do Vab = Va -Vb, where b is the initial point and a is the final point. If we take initial point as the point where potential becomes zero i.e at infinity, we get absolute potential.
So that way Vab will always be Va-Vb. Your answer must be right. I don't have Sadiku so I can't say why they adopted the strange equation, it may be based on change in convention or something else. But as far as Hayt goes, Vab = Va- Vb. And that equation remains universal.
Thanks for pointing out the error. The answer has been rectified.
If you still have any doubt, feel free to ask in the comment section. If my answer has any mistake then kindly point it out so that I can rectify it.