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Let sinx = n
Then,
⇒ 2n² - 3n -1
By Quadratic formula
⇒ -b+√b²-4ac/2a , -b-√b²-4ac/2a
⇒ -(-3) + √(-3)²-4(2)(-1) , -(-3) - √(-3)²-4(2)(-1)
⇒ 3 + √9+8 , 3 - √9+8
⇒ 3 + √17 , 3 - √17
Then sin x = 3+√17 , 3-√17
:)Hope this helps !!!
Then,
⇒ 2n² - 3n -1
By Quadratic formula
⇒ -b+√b²-4ac/2a , -b-√b²-4ac/2a
⇒ -(-3) + √(-3)²-4(2)(-1) , -(-3) - √(-3)²-4(2)(-1)
⇒ 3 + √9+8 , 3 - √9+8
⇒ 3 + √17 , 3 - √17
Then sin x = 3+√17 , 3-√17
:)Hope this helps !!!
Chandu1111111Chaman:
but what will be the value of x
please help
we are able to find the value of x only when 2sin²x - 3sinx -4 and not 2sin²x - 3sinx -1
did u get cleared
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