Math, asked by theanswerguru, 2 months ago

Please answer asap.

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Answers

Answered by Salmonpanna2022
2

Given:-

 \frac{7 \sqrt{3} }{ \sqrt{10} +  \sqrt{3}  }  -  \frac{2 \sqrt{5} }{ \sqrt{6} +  \sqrt{5}  } -  \frac{3 \sqrt{2} }{ \sqrt{15} + 3 \sqrt{2}  }   \\  \\

What to do:-

Simplify

Solution:-

Let's solve the problem

we have,

 \frac{7 \sqrt{3} }{ \sqrt{10} +  \sqrt{3}  }  -  \frac{2 \sqrt{5} }{ \sqrt{6} +  \sqrt{5}  } -  \frac{3 \sqrt{2} }{ \sqrt{15} + 3 \sqrt{2}  }   \\  \\

⟹ \frac{7 \sqrt{3} }{ \sqrt{10} +  \sqrt{3}  }  \times  \frac{ \sqrt{10} -  \sqrt{3}  }{ \sqrt{10}  -  \sqrt{3} }  -  \frac{2 \sqrt{5} }{ \sqrt{6}  +  \sqrt{5} }  \times  \frac{ \sqrt{6}  -  \sqrt{5} }{ \sqrt{6}  -  \sqrt{5} }  -  \frac{3 \sqrt{2} }{ \sqrt{15}  + 3 \sqrt{2} }  \times  \frac{ \sqrt{15}  - 3 \sqrt{2} }{ \sqrt{15}  - 3 \sqrt{2} }  \\  \\

⟹ \frac{7 \sqrt{3}( \sqrt{10} -  \sqrt{3}  ) }{(  \sqrt{10} +  \sqrt{3} )( \sqrt{10} -  \sqrt{3})   } -  \frac{2 \sqrt{5}( \sqrt{6} -  \sqrt{5}   )}{( \sqrt{6} +  \sqrt{5} )( \sqrt{6}   -  \sqrt{5}) }  -  \frac{3 \sqrt{2}( \sqrt{15}  - 3 \sqrt{2})  }{( \sqrt{15}  + 3 \sqrt{2})( \sqrt{15}  - 3 \sqrt{2})  }  \\  \\

⟹ \frac{7 \sqrt{3}( \sqrt{10}  -  \sqrt{3}  )}{( \sqrt{10}  {)}^{2} ( \sqrt{3} {)}^{2}  }  - \frac{2 \sqrt{5}( \sqrt{6} -  \sqrt{5} )  }{( \sqrt{6} {)}^{2} - ( \sqrt{5}   {)}^{2}  }  -  \frac{3 \sqrt{2}( \sqrt{15} - 3 \sqrt{2}  ) }{( \sqrt{15}  {)}^{2}  - (3 \sqrt{2}  {)}^{2} }  \\  \\

⟹ \frac{7 \sqrt{3}( \sqrt{10}  -  \sqrt{3}  )}{10 -  3 }  - \frac{2 \sqrt{5}( \sqrt{6} -  \sqrt{5} )  }{6 - 5}-\frac{3 \sqrt{2}( \sqrt{15} - 3 \sqrt{2}  ) }{15 - 18}  \\  \\

⟹ \frac{ \cancel{7} \sqrt{3}( \sqrt{10}  -  \sqrt{3}  )}{ \cancel{7 }}  - \frac{2 \sqrt{5}( \sqrt{6} -  \sqrt{5} )  }{1}-\frac{{  \cancel{3}} \sqrt{2}( \sqrt{15} -  {3} \sqrt{2}  ) }{ \cancel{3}}  \\  \\

⟹ \sqrt{3} ( \sqrt{10}  -  \sqrt{3} ) - 2 \sqrt{5} ( \sqrt{6}  -  \sqrt{5} ) +  \sqrt{2} ( \sqrt{15}  - 3 \sqrt{2} ) \\  \\

⟹ \sqrt{30}  - 3 - 2 \sqrt{30}  + 10 +  \sqrt{30}  - 6 \\  \\

⟹ \cancel{2 \sqrt{30} } - 9 -  \cancel{2 \sqrt{30} } + 10 \\  \\

⟹ - 9 + 10 \\  \\

⟹9 - 10 \\  \\

⟹1 \:  \:  \:  \: Ans. \\  \\

# Learn more:

Rationalize the denominator.

i. 1/(√7 + √2)

ii. 3/(2√5 - 3√2)

iii. 4/(7 + 4√3)

iv. (√5 - √3)/(√5 + √3)

https://brainly.in/question/2846541

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