Question

Please answer ASAP
C program for swapping of 2 numbers .

Answer 1

Hi friend,

This is the answer to your question:-
METHOD-1:-Using temporary variable.


#include <stdio.h>

  int main()

{

 int x, y, temp; 

 printf("Enter the value of x and y\n");

scanf("%d%d", &x, &y);  

printf("Before Swapping\nx = %d\ny = %d\n",x,y);  

temp = x; x = y; y = temp;  

printf("After Swapping\nx = %d\ny = %d\n",x,y);  

return 0;

 }

METHOD-2:-Using Call by reference.

#include <stdio.h> 

 void swap(int*, int*); 

 int main() { int x, y;  

printf("Enter the value of x and y\n");

scanf("%d%d",&x,&y);  

printf("Before Swapping\nx = %d\ny = %d\n", x, y);  

swap(&x, &y);  

printf("After Swapping\nx = %d\ny = %d\n", x, y);  

return 0;

}  

void swap(int *a, int *b)

{

int temp;  

temp = *b;

*b = *a;

*a = temp;

}


METHOD-3:-Without using third variable

#include <stdio.h>  

int main()

{

int a, b;  

printf("Enter two integers to swap\n");

scanf("%d%d", &a, &b);  

a = a + b;

b = a - b;

a = a - b;  

printf("a = %d\nb = %d\n",a,b);

return 0;

}

Hope it helps!

Answer 2

Answer -

• #include<studio.h>
• #include<conio.h>
• void main()
• {
• int a,b;
• clrscr();
• printf("enter any two numbers");
• scanf("%d%d",&a,&b);
• a=a+b;
• b=a-b;
• a=a-b;
• printf("a=%d",a);
• printf("\nb=%d",b);
• getch();
• }

Hope it will help you ❤️