Question

PLEASE ANSWER ASAP...
CLASS 10

Answer 1

Answer:

Step-by-step explanation:

Ao=oB

Angle OAB =angle OBA (angles equal to opp sides )

Therefore angle BAO=35°

In triangle AOB

35°+35°+angle O =180°(asp)

Angle O =180-70

Angle O =110°

Angle ACB=1/2 angle AOB(degree measure theorem )

Angle ACB =1/2×110

Angle ACB =55°

Angle CAB =90°(angle formed by circle)

Angle CAO +angle OAB =90°

Angle CAO =90-35

Angle CAO=55°