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x = 180° - (52° + x) ∵ △ABC is an iscoceles △
x = 180° - 52° - x
x + x = 180° - 52°
2x = 128°
x = 128°/2
x = 64°
y = z = (180° - x ) ÷ 2 ∵ △ACD is an iscoceles △
y = z = (180° - 64°) ÷ 2
y = z = 116°/2 = 58°
Answers:
x = 64°
y = 58°
z = 58°
x = 180° - 52° - x
x + x = 180° - 52°
2x = 128°
x = 128°/2
x = 64°
y = z = (180° - x ) ÷ 2 ∵ △ACD is an iscoceles △
y = z = (180° - 64°) ÷ 2
y = z = 116°/2 = 58°
Answers:
x = 64°
y = 58°
z = 58°
Answered by
40
Answer:
answer x=64
y=58
z=58...........
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