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A ball of mass 10 kg moving with 10m/s suddenly bursts into two pieces one piece of mass 6 kg moves with the same direction with velocity 18 m/s. the other piece moves with what velocity?
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The moderators deleted my answer, but that didn't stopped me : ) answer is below
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Steph0303:
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Hey there!
According to law of conservation of linear momentum, Total momentum of the system is conserved.
Let the mass of ball be M = 10kg.
Velocity of the ball be V = 10m/s.
And,
Mass of the first piece be m1 = 6kg.
Velocity v1 = 18m/s.
Mass of second piece m2 = 10 - 6 = 4kg.
Velocity v2
Now applying law of conservation of linear momentum.
![MV = m_{1}v_{1}+m_{2}v_{2} \: MV = m_{1}v_{1}+m_{2}v_{2} \:](https://tex.z-dn.net/?f=MV+%3D+m_%7B1%7Dv_%7B1%7D%2Bm_%7B2%7Dv_%7B2%7D+%5C%3A+)
![10 ( 10) = 6 ( 18) + 4 (v_2) \\ \\ <br /><br />100 = 108 + 4v_{2} \\ \\ 100 - 108 = 4v_{2} \\ \\ v_{2} = \frac{ - 8}{4} = - 2 10 ( 10) = 6 ( 18) + 4 (v_2) \\ \\ <br /><br />100 = 108 + 4v_{2} \\ \\ 100 - 108 = 4v_{2} \\ \\ v_{2} = \frac{ - 8}{4} = - 2](https://tex.z-dn.net/?f=10+%28+10%29+%3D+6+%28+18%29+%2B+4+%28v_2%29+%5C%5C+%5C%5C+%3Cbr+%2F%3E%3Cbr+%2F%3E100+%3D+108+%2B+4v_%7B2%7D+%5C%5C+%5C%5C+100+-+108+%3D+4v_%7B2%7D+%5C%5C+%5C%5C+v_%7B2%7D+%3D+%5Cfrac%7B+-+8%7D%7B4%7D+%3D+-+2)
Therefore, The second piece will moves with Velocity 2m/s in the opposite direction.
According to law of conservation of linear momentum, Total momentum of the system is conserved.
Let the mass of ball be M = 10kg.
Velocity of the ball be V = 10m/s.
And,
Mass of the first piece be m1 = 6kg.
Velocity v1 = 18m/s.
Mass of second piece m2 = 10 - 6 = 4kg.
Velocity v2
Now applying law of conservation of linear momentum.
Therefore, The second piece will moves with Velocity 2m/s in the opposite direction.
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