please answer atleast ome question if you know I'll mark as brainliest please
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Answer:
Answer of question no. 26 is 2,9 and 16.
Explanation:
Let the three consecutive terms of the AP be
a
−
d
,
a
,
and
a
+
d
.
Given:
Sum of these three terms is 27.
Product of the terms is 288.
(
a
−
d
)
+
a
+
(
a
+
d
)
=
27
3
a
=
27
a
=
9
and
(
a
−
d
)
(
a
)
(
a
+
d
)
=
288
Now put the value of 'a' in the above equation we get,
(
9
−
d
)
(
9
)
(
9
+
d
)
=
288
729
−
9
d
2
=
288
9
d
2
=
729
−
288
9
d
2
=
441
d
2
=
441
9
d
2
=
49
d
=
√
49
d
=
7
Therefore three consecutive terms are:
(
9
−
7
)
=
2
,
(
9
)
,
and
(
9
+
7
)
=
16.
Hence the three consecutive terms are:
2
,
9
,
and
16
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