Math, asked by dipalisamaddar9249, 8 months ago

please answer both... it's urgent ​

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Answered by aliahmad46
2

Answer:

H) 1/2×base ×height = area

1/2×20×H=20so height =2cm

I) let each side of square be equal to x cm

so area = x²

increased lenght of side = 3x/2so area = 9x²/4

THEREFORE ratio = 9x²/4:x²

=9:4

Thanks.. please follow

Answered by tennetiraj86
1

Step-by-step explanation:

H)base of the triangle =(b)=20cm

area of the triangle=20cm²

=>bh/2=20

=>20×h/2=20

=>10×h=20

=>h=20/10

=>h=2 cm

height=2 cm

option b

I)Let the side of the square=a units

Area of the square=a² sq.units

If the side is increased by 50%

=>a+50%×a

=>a+(50/100)a

=>a+a/2

=>3a/2

new side =3a/2 units

area of the new square =(3a/2)(3a/2)

=9a²/4 sq.units

Their ratio=9a²4:a²

=>9:4

Option b

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