Question

☺ PLEASE ANSWER BOTH OF THEM IN UR NOTEBOOK AND GIVE THE PICTURE.

⚠ NO SPAMMING

Answer 1

Hey

13)

By base changing theorem :

$\frac{ { log }^{2}(a) }{ log(b). log(c) } + \frac{ { log }^{2}(b) }{ log(a). log(c) } + \frac{ { log }^{2}(c) }{ log(a). log(b) } = 3$

${ log }^{3} (a) + { log }^{3} (b) + { log }^{3} (c) = 3. log(a) . log(b) . log(c)$

$log(a) + log(b) + log(c) = 0$

$abc = 1$


For 14)

Substitute :

$log_{2}(3) = m$
And reduce :

$y = \sqrt{m(m + 2)(m + 4)(m + 6) + 16} - (m + 2)(m + 4) + 10$

$y = ( {m}^{2} + 6m + 4) - ( {m}^{2} + 6m + 8) + 10$

$y = 10 - 4 = 6$

Answer 2

Answer:

a molecule is General a group of two are more than atoms that are chemically bonded