Question

please answer both questions ​

Answer 1

Explanation:

1. Given that HCF = 9 and the numbers are 306 and 657.

LCM =?

We know that LCM* HCF= product of two numbers

→ LCM*9=306*657

→ LCM=201042/9=22338 .

2. If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5

Prime factorisation of 6n = (2 ×3)n

It can be observed that 5 is not in the prime factorisation of 6n.

Hence, for any value of n, 6n will not be divisible by 5.

Therefore, 6n cannot end with the digit 0 for any natural number n.

hope it helps u.

Answer 2

Answer:

the answer given above is correct