Question

please answer both questions with explanation . Copied answers and spammers will be reported​

Answer 1

$\huge\red{AnswEr}$

For a passenger in the train, the car has one velocity component in the north direction due to its absolute motion and another velocity component in the west direction due to relative motion with respect to the passenger (since the train is moving along east).

Since both velocities are same:

Angle made by velocity vector with x-axis, tan\theta$=\frac{ - v}{v} \implies \theta = 135°tanθ= </p><p>v</p><p>−v</p><p> </p><p> ⟹θ=135°$

i.e. along west- north direction.

Hence, option B is correct

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2nd answer is in attachment

Answer 2

Answer:

For a passenger in the train, the car has one velocity component in the north direction due to its absolute motion and another velocity component in the west direction due to relative motion with respect to the passenger (since the train is moving along east).

Since both velocities are same:

Angle made by velocity vector with x-axis, tan\theta=\frac{ - v}{v} \implies \theta = 135°tanθ= v −v ⟹θ=135°=v−v⟹θ=135°tanθ=v−v⟹θ=135°

i.e. along west- north direction.

Hence, option B is correct