Question

please answer both the question....

I WILL SURELY MARK YOU AS BRAINLIEST......​

Answer 1

We know that

Gravitational force is inversely proportional to square of the distance between two bodies

suppose c is the constant (mass of two body and value of G )

At initial

F(G ) = C/r^2

when distance tripled

F`(G) = C/9r^2

Now

F'(G )/F(G)= 1/9

R'(G) = F(G) /9

force become 1/9 time of its initial value (decrease )

We know that gravitational force is directly proportional to mass of the body

Taking C as constant (Distance between two body and gravitational constant)

F(G) = CM1m2

when mass become two times

F`(G) = 2M1m2 C

Now

F`(G) /F(G) = 2

F`(G) =F 2(G)

Conclusion

• when the distance between the two bodies increases gravitational forces decreases by square of the distance between them.
• when there is change in mass of a body then gravitational force increases.

Answer 2

Answer:

for 1 st qs : force decreases by 9 times

for 2nd qs force doubles

Explanation:

a) F=(Gm1m2)/r^2--------------(1)

given r becomes 3r

so new F=(Gm1m2)/9r^2--------(2)

dividing (2) by (1) we get,

new F=F/9

b) F=(Gm1m2)/r^2------------(1)

given m1 becomes 2m1

so new F=(G2m1m2)/r^2----------------------(2)

dividing (1) by (2) we get

new F=2F