Question

Please answer both the questions.​

Answer 1

Answer:

BIC=130 and BAI=40

Step-by-step explanation:

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Answer 2

Given equation

x(x + 1)(x + 3)(x + 4) = 180

⇒ [(x + 0)(x + 4)] [(x + 1)(x + 3)] = 180

⇒ (x2 + 4x)(x2 + 4x + 3) – 180 = 0

Put  x2 + 4x = y,

Then it becomes  y(y + 3) – 180 = 0

⇒ y2 + 3y – 180 = 0

⇒ y2 + 15y – 12y – 180 = 0

⇒ y(y + 15) – 12(y + 15) = 0

⇒ ( y + 15)(y – 12) = 0

⇒ y + 15 = 0  or  y – 12 = 0

⇒ y = - 15 or  y = 12